(i) Write the electron-dot structures for sodium, oxygen and magnesium.
(ii) Show the formation of Na2O and MgO by the transfer of electrons.
(iii) What are the ions present in these compounds?
(i) The electron-dot structures for sodium, oxygen, and magnesium are: Na•, •O•, and Mg•, respectively, where the dots represent the valence electrons. (ii)The formation of Na₂O and MgO involves the transfer of electrons from metal atoms (Na and Mg) to oxygen atoms, resulting in the formation of oppositely charged ions (Na+, Mg²+, and O²⁻) that are held together by electrostatic attraction, creating ionic compounds.
Formation of Na₂O:
Two sodium atoms (Na) each lose one electron to become sodium ions (Na⁺).
An oxygen atom (O) gains these two electrons to become an oxide ion (O²⁻).
The resulting oppositely charged ions are attracted to each other, forming Na₂O.
Formation of MgO:
A magnesium atom (Mg) loses two electrons to become a magnesium ion (Mg²⁺).
An oxygen atom (O) gains these two electrons to become an oxide ion (O²⁻).
The oppositely charged ions are attracted to each other, forming MgO.(iii) It seems like the user is asking about the ions present in the compounds Na₂O, MgO, NaCl, and Na₂CO₃. Here’s a breakdown:
Na₂O (sodium oxide):: 2 sodium ions (Na⁺) and 1 oxide ion (O²⁻).
MgO (magnesium oxide):: 1 magnesium ion (Mg²⁺) and 1 oxide ion (O²⁻).
NaCl (sodium chloride):: 1 sodium ion (Na⁺) and 1 chloride ion (Cl⁻).
Na₂CO₃ (sodium carbonate):: 2 sodium ions (Na⁺) and 1 carbonate ion (CO₃²⁻).
Here’s a more detailed explanation:
Sodium (Na):
Sodium has one valence electron, so it’s represented by Na with one dot (Na•).
Oxygen (O):
Oxygen has six valence electrons, so it’s represented by O with six dots (•O•).
Magnesium (Mg):
Magnesium has two valence electrons, so it’s represented by Mg with two dots (Mg•).