Answers

JEE Mains (Friction)

A body of mass m=10−2 kg is moving in a medium and experiences a frictional force F=−kv2. Its initial speed is v0= 10 ms−1. If, after 10 s, its energy is ⅛ mv02, the value of k will be

(a) 10−3 kg m−1

(b) 10−3 kg s−1

(c) 10−4 kg m−1

(d) 10−1 kg m−1 s−1

20/11/2024

Physics

JEE-MAINS