If all the number from 7 to 59, which are divisible by 3 are arranged in descending order then which number
will be at 10th place from the bottom ?
(A) 36 (B) 39 (C) 30 (D) 27
What you’re solving for Finding the 10th number from the bottom when numbers divisible by 3 between 7 and 59 are arranged in descending order. What’s given in the problem Numbers between 7 and 59. Numbers are divisible by 3. Numbers are arranged in descending order. How to solve Find the numbers divisible by 3 between 7 and 59, arrange them in descending order, and then identify the 10th number from the bottom.
Step 1: . Find the first and last number divisible by 3 in the given range. The first number greater than 7 divisible by 3 is 9. The last number less than 59 divisible by 3 is 57.
Step 2: . List the numbers divisible by 3 in descending order. The sequence is: 57,54,51,48,45,42,39,36,33,30,27,24,21,18,15,12,9
Step 3: . Identify the 10th number from the bottom. Counting from the end of the list, the 10th number is 30
Solution
The 10th number from the bottom is 30.