Three persons A, B and C are Standing in a queue. There are five persons between A and B and eight
persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be
the minimum number of persons in the queue.
(A) 41 (B) 40 (C) 28 (D) 27
The minimum number of persons in the queue. What’s given in the problem There are (5) persons between A and B. There are (8) persons between B and C. There are (3) persons ahead of C. There are (21) persons behind A. Helpful information To minimize the number of people, B should be between A and C. How to solve Calculate the minimum number of persons in the queue by considering the overlapping arrangement.Step 1 . Determine the relative positions of A, B, and C for the minimum number of persons For the minimum number of persons, B must be between A and C. The order is C, B, A. Step 2 . Calculate the number of persons between C and A Persons between C and A = Persons between C and B + Persons between B and A + 2(for B and C) Persons between C and A = (8+5+2=15)
Step 3 . Calculate the total number of persons in the queue Total persons = Persons ahead of C + Persons between C and A + Persons behind A + 1 (for A) Total persons =(3+15+21+1=40)
Solution
The minimum number of persons in the queue is (28).