(i) Let A be an event in which the first player gets the card which has a perfect square greater than 500. Favourable outcomes = 529, 576, 625, 676, 729, 784, 841, 900 and 961. Number of Favourable outcomes = 9. Total number of outcomes = 1000. Let P(A) be the probability of event A. P(A) = (Number of Favourable outcomes)/(Total Number of outcomes). P(A) = 9/1000. Therefore, Probability for the first player to win a prize is (9/1000). (ii) Let B be an event in which the second player wins a prize, if the first player had already won. Favourable outcomes = 529, 576, 625, 676, 729, 784, 841, 900 and 961. Number of Favourable outcomes = 9 - 1 [we subtract 1 becuase the first player already a prize and that number will not be used again so there will be 1 less perfect square number after 500] Number of Favourable outcomes = 8 Total number of outcomes = 1000 Let P(B) be the probability of event A . P(B) = (Number of Favourable outcomes)/(Total Number of outcomes) P(B) = 8/1000 Thus, probability of the second player to win a prize is (8/1000).