Find the sum of first 17 terms of an AP whose 4th and 9th terms are –15 and –30 respectively.
If Sn denotes the sum of first n terms of an AP, prove that S12 = 3(S8 –S4)
Which term of the AP: –2, –7, –12,… will be –77? Find the sum of this AP upto the term –77.
The first term of an AP is –5 and the last term is 45. If the sum of the terms of the AP is 120, then find the number of terms and the common difference.
How many numbers lie between 10 and 300, which when divided by 4 leave a remainder 3?
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